Evaluating a polynomial function

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To evaluate a polynomial function at a number means to find the output for that input.
You simply substitute the value in place of every xx and simplify.
eval_poly_sub.png
For example, to find p(2)p(2) for p(x)=x2+3x−2p(x) = x^2 + 3x - 2, replace each xx with 22: (2)2+3(2)−2=4+6−2=8(2)^2 + 3(2) - 2 = 4 + 6 - 2 = 8.
Be careful to apply the power and multiplication before adding.
Often a question gives you the value of pp at some point and asks you to find an unknown coefficient.
You substitute the point in, set the result equal to the given value, and solve.
This turns the function into an equation for the unknown.
Evaluating also connects to division through the remainder theorem.
The remainder when p(x)p(x) is divided by (x−a)(x - a) is exactly p(a)p(a).
So instead of doing long division, you can just evaluate p(a)p(a).

Worked examples

For p(x)=2x2−x+3p(x) = 2x^2 - x + 3, what is p(2)p(2)?
Substitute 22 for each xx: 2(2)2−(2)+32(2)^2 - (2) + 3.
So p(2)=8−2+3=9p(2) = 8 - 2 + 3 = 9.
Given p(x)=x3+kx2−4x+2p(x) = x^3 + kx^2 - 4x + 2 and p(1)=5p(1) = 5, find kk.
Substitute x=1x = 1: 1+k−4+2=k−11 + k - 4 + 2 = k - 1.
Setting k−1=5k - 1 = 5 gives k=6k = 6.
What is the remainder when p(x)=x3−2x+4p(x) = x^3 - 2x + 4 is divided by (x−2)(x - 2)?
By the remainder theorem, the remainder is p(2)p(2).
So it is (2)3−2(2)+4=8−4+4=8(2)^3 - 2(2) + 4 = 8 - 4 + 4 = 8.

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