Forming Linear inequality in a word problem

An SAT Math micro-topic under Linear inequality word problems (Algebra). Free to read — no account needed.

Forming a linear inequality is two steps: write the quantity as an algebraic expression, then compare it to a limit with the correct sign. The sign comes straight from the wording — "at most" is ≤\le, "at least" is ≥\ge, "more than" is >>, and "less than" is <<.
Build the expression before choosing the sign. "A driver weighing 180180 pounds loads 4040-pound boxes onto an elevator that holds at most 15001500 pounds": the total weight is 180+40b180 + 40b, and "at most 15001500" gives 180+40b≤1500180 + 40b \le 1500.
Watch whether the boundary is included. "At most" and "at least" include the limit, so use ≤\le or ≥\ge; "more than" and "less than" exclude it, so use >> or <<. "Must sell more than $5000" is s>5000s > 5000, not s≥5000s \ge 5000.
Percent and comparison phrasing need care. "10%10\% greater than xx" means x+0.1x=1.1xx + 0.1x = 1.1x, so "no district has a population more than 10%10\% greater than another" becomes y≤1.1xy \le 1.1x. Decide which quantity is larger before picking the direction of the sign.

Worked examples

A host pays a $200 flat fee plus $18 per guest and wants to spend no more than $1500. Write an inequality for the number of guests gg.
The total cost is 18g+20018g + 200, and "no more than $1500" gives 18g+200≤150018g + 200 \le 1500.
A student has $45 and earns $15 per hour, and needs at least $120. Write an inequality for the hours hh.
The total is 15h+4515h + 45, and "at least $120" gives 15h+45≥12015h + 45 \ge 120.
Company A charges 100+75h100 + 75h and company B charges 150+50h150 + 50h. Write an inequality for when A is cheaper than B.
"Cheaper" means A's cost is less than B's: 100+75h<150+50h100 + 75h < 150 + 50h.

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