Power of a product rule

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When a whole product is raised to a power, that power lands on each factor.
So (ab)n=anbn(ab)^n = a^n b^n.
Every part inside the brackets is raised to the power.
Do not forget the number in front.
In (2x)3(2x)^3, both 22 and xx are cubed: 23×x3=8x32^3 \times x^3 = 8x^3.
A common mistake is to cube only the xx and leave the 22 alone.
The rule extends to factors that already have exponents.
For (2x2)2(2x^2)^2, raise each part: 22×(x2)2=4x42^2 \times (x^2)^2 = 4x^4, using (xa)b=xab(x^a)^b = x^{ab}.
So (x2)2=x2×2=x4(x^2)^2 = x^{2 \times 2} = x^4.
It also works with fractional powers, which are roots.
For (2x6)12(2x^6)^{\frac{1}{2}}, take each factor to the 12\frac{1}{2}: 212×(x6)122^{\frac{1}{2}} \times (x^6)^{\frac{1}{2}}.
Since (x6)12=x6×12=x3(x^6)^{\frac{1}{2}} = x^{6 \times \frac{1}{2}} = x^3, this is 212x32^{\frac{1}{2}} x^3.

Worked examples

Simplify (3x)2(3x)^2.
Raise each factor to the power: 32×x23^2 \times x^2.
So (3x)2=9x2(3x)^2 = 9x^2.
Simplify (2x2)2(2x^2)^2.
Raise each factor: 22×(x2)22^2 \times (x^2)^2.
Since (x2)2=x4(x^2)^2 = x^4, this is 4x44x^4.
Simplify (2x6)12(2x^6)^{\frac{1}{2}}.
Raise each factor to 12\frac{1}{2}: 212×(x6)122^{\frac{1}{2}} \times (x^6)^{\frac{1}{2}}.
Since (x6)12=x3(x^6)^{\frac{1}{2}} = x^3, this is 212x32^{\frac{1}{2}} x^3.

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