Reframing the question

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Reframing means rewriting what you are given so it lines up with what you need to find.
Instead of grinding through a direct solution, you reshape the expression or equation.
A few standard moves cover most cases.
One move is to rewrite an expression so a needed piece appears.
To express 2x+72x + 7 in terms of (x+3)(x + 3), build from 2(x+3)=2x+62(x + 3) = 2x + 6.
Then 2x+7=2(x+3)+12x + 7 = 2(x + 3) + 1.
Another move is to treat a whole chunk as a single variable.
In 2x−3−2+3−2x=4\frac{2x - 3}{-2} + 3 - 2x = 4, let m=3−2xm = 3 - 2x, so 2x−3=−m2x - 3 = -m.
The equation becomes −m−2+m=4\frac{-m}{-2} + m = 4, which is far simpler.
You can also combine given equations to produce exactly what is asked.
To find m2+n2−2mnm^2 + n^2 - 2mn from m2+3mn=5m^2 + 3mn = 5 and n2−5mn=12n^2 - 5mn = 12, add them.
The result m2+n2−2mn=17m^2 + n^2 - 2mn = 17 is the expression you wanted, without ever finding mm or nn.

Worked examples

Rewrite 3x+103x + 10 in terms of (x+2)(x + 2). \ Since 3(x+2)=3x+63(x + 2) = 3x + 6, that is 44 less than 3x+103x + 10. \ So 3x+10=3(x+2)+43x + 10 = 3(x + 2) + 4.
Given a+2b=7a + 2b = 7 and a−b=1a - b = 1, find 2a+b2a + b without solving for aa and bb. \ Add the two equations: (a+2b)+(a−b)=7+1(a + 2b) + (a - b) = 7 + 1. \ This gives 2a+b=82a + b = 8.
Solve (x+1)2−5(x+1)+6=0(x + 1)^2 - 5(x + 1) + 6 = 0 by letting u=x+1u = x + 1. \ The equation becomes u2−5u+6=0u^2 - 5u + 6 = 0, which factors as (u−2)(u−3)=0(u - 2)(u - 3) = 0, so u=2u = 2 or u=3u = 3. \ Since u=x+1u = x + 1, we get x=1x = 1 or x=2x = 2.

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