Solving inequalities

An SAT Math micro-topic under Solving linear equations and inequalities (Algebra). Free to read — no account needed.

An inequality compares two sides using <<, >>, ≤\leq, or ≥\geq instead of ==.
To solve it, you find all the values of xx that make it true.
The steps are the same as solving an equation: gather the xx-terms on one side and the numbers on the other.
Take 3x+5<2x+103x + 5 < 2x + 10.
Subtract 2x2x from both sides: x+5<10x + 5 < 10.
Subtract 55 from both sides: x<5x < 5.
So every number less than 55 is a solution.
nl_x_lt_5.png
Here is the one rule that is different from equations.
If you multiply or divide both sides by a negative number, flip the inequality sign.
For example, −x≥4-x \geq 4.
Multiply both sides by −1-1, and the ≥\geq becomes ≤\leq, giving x≤−4x \leq -4.
nl_flip.png
The answer to an inequality is usually a range, not a single number.
On a number line, an open circle means the endpoint is not included (for << or >>).
A filled circle means the endpoint is included (for ≤\leq or ≥\geq).
A system of inequalities is two or more inequalities at once.
A point is a solution only if it satisfies every inequality in the system.
If it fails even one, it is not a solution.

Worked examples

Solve 2x+3<x+92x + 3 < x + 9.
Subtract xx from both sides: x+3<9x + 3 < 9.
Subtract 33 from both sides: x<6x < 6.
nl_x_lt_6.png
Solve 4−2x≥104 - 2x \geq 10.
Subtract 44 from both sides: −2x≥6-2x \geq 6.
Divide both sides by −2-2 and flip the sign: x≤−3x \leq -3.
nl_x_le_neg3.png
Solve −3x<12-3x < 12.
Divide both sides by −3-3 and flip the sign: x>−4x > -4.
So every number greater than −4-4 is a solution.
nl_x_gt_neg4.png

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