Understanding when to substitute unknowns with numbers

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Some questions can be solved much faster by choosing your own numbers for the unknowns instead of doing the algebra.
The idea is to substitute an easy value, work out the answer, and then see which answer choice matches.
Here is the whole method in one example.
Suppose a question asks which expression is equivalent to 2(x+3)2(x + 3), with choices 2x+32x + 3, 2x+62x + 6, x+6x + 6, and 2x+52x + 5.
Since everything is written in terms of xx, pick a simple value like x=1x = 1.
The expression becomes 2(1+3)=82(1 + 3) = 8.
Now test the choices at x=1x = 1: they give 55, 88, 77, and 77.
Only 2x+62x + 6 gives 88, so it is the answer.
This works whenever two things are true.
First, the answer is a relationship — a fraction, percent, ratio, or an expression in the variables — not one fixed number.
For instance, if a question asks what fraction of a class passed and gives only fractions, the class size does not matter: 1830\frac{18}{30} and 610\frac{6}{10} are the same fraction, so you can just assume 3030 students.
Second, nothing fixes the unknowns to particular values.
When both hold, any numbers you pick give the same answer, so choose easy ones.
substitute_decision.png
It does not work when the question asks for a specific value that the information pins down.
For example, "a number increased by 55 equals 1212" forces the number to be exactly 77.
Guessing n=3n = 3 gives 88, not 1212, so a random value fails.
Whenever a constraint (an equation you must solve) fixes the unknown, solve it instead of assuming.
For questions built entirely on percentages, 100100 is the perfect number to assume.
Say a price rises 20%20\% and then falls 10%10\%: start at $100\$100, go up to $120\$120, then down to $108\$108.
Reading the final answer off 100100 is far easier than tracking the percentages in symbols.
Two tips make this reliable.
Pick small, easy numbers, but avoid 00 and 11, because they often make several choices give the same result.
And if two choices happen to match your first number, just try a second number to break the tie.

Worked examples

Which of the following is equivalent to 3(x−2)+43(x - 2) + 4?
(A) 3x−23x - 2
(B) 3x+23x + 2
(C) x+2x + 2
(D) 3x+63x + 6
Since the question and every choice are in terms of xx, pick a simple value like x=2x = 2.
The expression becomes 3(2−2)+4=43(2 - 2) + 4 = 4.
Testing the choices at x=2x = 2: (A) gives 44, (B) gives 88, (C) gives 44, and (D) gives 1212.
Both (A) and (C) give 44, so try x=3x = 3: the expression is 3(1)+4=73(1) + 4 = 7, (A) gives 77, and (C) gives 55.
Only (A) matches, so (A) is the answer.
A shirt's price is raised by 30%30\% and then lowered by 10%10\%. What percent of the original price is the final price?
(A) 120%120\%
(B) 117%117\%
(C) 121%121\%
(D) 90%90\%
Since it is all percentages with no fixed price, assume the original is $100\$100.
A 30%30\% rise gives $100→$130\$100 \to \$130.
A 10%10\% drop gives $130→$130−$13=$117\$130 \to \$130 - \$13 = \$117.
So the final price is 117%117\% of the original, which is (B).
Can you solve 2n+5=172n + 5 = 17 by assuming any value for nn?
No — this equation constrains nn to one specific value, so you must solve it.
Subtracting 55 from both sides gives 2n=122n = 12, so n=6n = 6.
A guess like n=3n = 3 would give 2(3)+5=112(3) + 5 = 11, not 1717, so only n=6n = 6 works.

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