How the SAT tests this, with worked examples — plus the 2 skills it covers. Free to read, no account needed.
These are linear word problems whose answer is a range rather than a single value. The modelling is identical; the extra step is turning a phrase into the right inequality sign.
The distinction that matters is whether the boundary value itself counts. At least and no more than include it, giving ≥ and ≤. More than and fewer than exclude it, giving > and <.
So "a budget of at most $200" becomes cost≤200, while "more than 10 attendees" becomes n>10.
Solve exactly as you would an equation, with one exception: multiplying or dividing by a negative number flips the sign.
Finally, check the answer against the situation. Counts of people or items must be whole numbers, so a solution of n>10.4 means 11 or more — and the answer choices will include 10.4 for anyone who stops at the algebra.
Worked examples
Tickets cost $15 each and the budget is at most $200. How many can be bought? At most includes the boundary
15n≤200⇒n≤13.33
Tickets are whole, so at most 13.
A van holds more than 8 boxes but no more than 15. Write this as an inequality. More than excludes 8; no more than includes 15
8<b≤15
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