Percentages

How the SAT tests this, with worked examples — plus the 4 skills it covers. Free to read, no account needed.

Percent means out of one hundred, so 18%18\% is 0.180.18. Converting to a decimal first makes nearly every question here mechanical.
To increase by 20%20\%, multiply by 1.21.2; to decrease by 20%20\%, multiply by 0.80.8. Using multipliers rather than working out the change and adding it separately avoids most errors and makes repeated changes easy.
et_percent_change.png
That picture shows the most tested idea in the topic. An increase followed by a decrease of the same percentage does not return you to where you started, because the second percentage is taken of a larger number.
Percent change compares the change to the original amount
percent change=new−oldold×100{\text{percent change} = \frac{\text{new} - \text{old}}{\text{old}} \times 100}
Dividing by the new value instead is the single commonest mistake, and that wrong answer is always offered.
Reverse questions give you the final amount and ask for the original. Divide rather than multiply: if a price after a 25%25\% rise is $50\$50, the original was 501.25=$40\frac{50}{1.25} = \$40.

Worked examples

A price of $80\$80 rises by 15%15\%. What is the new price?
Multiply by the increase multiplier
80×1.15=92{80 \times 1.15 = 92}
A value goes from 4040 to 5252. What is the percent increase?
Compare the change with the original
52−4040×100=30%{\frac{52-40}{40} \times 100 = 30\%}
Dividing by 5252 instead gives about 23%23\%, which will be among the choices.
A jacket costs {
$66} after a {12
%} discount. What was the original price?
  • A{
$73.92}
(B) {
$75}
The sale price is 0.880.88 of the original, so divide: {
frac66660.880.88 = 75}, making (B) correct. (A) adds {12
%} to the sale price, which is the trap.

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All the skills in Percentages