An SAT Math micro-topic under Area and volume (Geometry and trigonometry). Free to read — no account needed.
Three-dimensional figures are handled with a small toolkit of formulas, so the work is mostly about choosing the right one and supplying the missing measurement.
For a cube of edge s, the six identical square faces give a surface area of 6s2, and the volume is s3. For a rectangular box with length l, breadth b and width w, there are three pairs of rectangular faces, so the surface area is 2lb+2bw+2lw and the volume is lbw.
For curved solids: a cylinder of radius r and height h has volume πr2h; a sphere of radius r has surface area 4πr2; and a pyramid has volume 31×base area×h.
A very common two-step pattern is to back out a length from a given quantity and then use it. If a cube has surface area 54, then 6s2=54 gives s=3, and its volume is 33=27. Recognising which formula links what you are given to what you are asked is the whole skill.
Worked examples
A cube has surface area 96 square inches. From 6s2=96 we get s2=16, so s=4 inches. Its volume is then s3=43=64 cubic inches.
A sphere has diameter 14, so its radius is 7. Using surface area 4πr2 with π=722: 4×722×72=616 square units.
A cylinder has radius 4 and height 10. Its volume is πr2h=π×42×10=160π.
Is this one of the topics costing you points?
Take the free 10-question diagnostic for a predicted SAT score and a breakdown of which domains are costing you points.