Basic exponentials

An SAT Math micro-topic under Quadratic and exponential word problems (Advanced Math). Free to read — no account needed.

An exponential function is written y=a⋅bxy = a \cdot b^x, where the variable xx appears in the exponent. Its defining feature is that increasing xx by 11 multiplies yy by the constant factor bb, instead of adding a fixed amount as a straight line would.
Whether the curve grows or decays depends on bb. When b>1b > 1 each step multiplies by more than one, so the values rise faster and faster: exponential growth. When 0<b<10 < b < 1 each step multiplies by less than one, so the values shrink towards zero without ever reaching it: exponential decay. Both curves pass through (0,a)(0, a).
exponential_growth_decay.png
A useful consequence: because an exponential never turns around, on a domain that starts at x=0x = 0 its largest or smallest value always sits at x=0x = 0. A decreasing (decay) function takes its maximum at x=0x = 0, while an increasing (growth) function takes its minimum at x=0x = 0 — in each case that value is the starting amount aa.
exponential_max_min.png
This multiplicative behaviour is why percentage change is exponential. A quantity decaying 8%8\% per hour is multiplied by 0.920.92 each hour, not reduced by a flat amount, so its graph curves rather than falling in a straight line.

Worked examples

A 100100 g sample decays 8%8\% per hour, so each hour it is multiplied by 1−0.08=0.921 - 0.08 = 0.92: after one hour 100×0.92=92100 \times 0.92 = 92 g, and after two hours 92×0.92≈8592 \times 0.92 \approx 85 g. The drop is not a flat 88 g each hour, which is what makes it exponential rather than linear.
For the growth function y=5⋅2xy = 5 \cdot 2^x, the starting value at x=0x = 0 is 55, and every increase of 11 in xx doubles yy: 5,10,20,40,…5, 10, 20, 40, \dots So yy is multiplied by 22 at each step rather than having a fixed amount added.
Consider the decay function y=100⋅(0.92)xy = 100 \cdot (0.92)^x for x≥0x \ge 0. Its value is largest at the start: at x=0x = 0, y=100y = 100, and it only decreases afterwards, so its maximum is at x=0x = 0. A growth function behaves the opposite way, taking its minimum at x=0x = 0.

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