Finding zeros of a function

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A zero of a function ff is any input xx for which f(x)=0f(x) = 0. Because the output is zero there, the graph of the function crosses or touches the xx-axis at each zero.
function_zeros.png
The figure shows both kinds. At one zero the curve passes straight through the axis (a simple zero); at another it just touches and turns back — a double zero, which happens when a factor appears twice.
To find zeros from factors, set each factor to zero. For f(x)=(x−1)(x−2)2f(x) = (x - 1)(x - 2)^2, the zeros are x=1x = 1 and x=2x = 2. Even though (x−2)(x - 2) appears twice, x=2x = 2 counts as one distinct zero (a double zero).
This is the factor idea in reverse: if (x−a)(x - a) is a factor of a polynomial, then x=ax = a is a zero, because substituting aa makes that factor 00. So if 3x+43x + 4 is a factor, set 3x+4=03x + 4 = 0 to get the zero x=−43x = -\frac{4}{3}.

Worked examples

Find the zeros of f(x)=x(x+5)f(x) = x(x + 5).
Set each factor to zero: x=0x = 0 or x+5=0x + 5 = 0.
So the zeros are x=0x = 0 and x=−5x = -5.
How many distinct zeros does g(m)=m2(2m−1)(m+2)3(m−2)4g(m) = m^2(2m - 1)(m + 2)^3(m - 2)^4 have?
Set each distinct factor to zero: m=0m = 0, m=12m = \frac{1}{2}, m=−2m = -2, m=2m = 2.
Repeated factors still give one value each, so there are 44 distinct zeros.
Find the zeros of y=x3−3x2−4x+12y = x^3 - 3x^2 - 4x + 12.
Factor by grouping: x2(x−3)−4(x−3)=(x2−4)(x−3)=(x−2)(x+2)(x−3)x^2(x - 3) - 4(x - 3) = (x^2 - 4)(x - 3) = (x - 2)(x + 2)(x - 3).
The zeros are x=2x = 2, x=−2x = -2, and x=3x = 3.

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